Mutual Induction
The phenomenon in which a change of current in one coil induces an emf in a neighbouring coil.
Definition
When the current in one coil changes, the magnetic flux linked with a nearby coil also changes, inducing an emf in it. This is called mutual induction. The coefficient of mutual induction is called mutual inductance \(M\).
Mathematical Expression
- If current in coil 2 is \(I_2\), then flux linkage with coil 1:
\[ N_1 \Phi_1 = M I_2 \] - Induced emf in coil 1:
\[ \varepsilon_1 = -M \frac{dI_2}{dt} \] - Similarly, if current in coil 1 is \(I_1\), emf in coil 2 is:
\[ \varepsilon_2 = -M \frac{dI_1}{dt} \]
Thus, emf in one coil is proportional to the rate of change of current in the other coil.
Derivation for Two Co-axial Solenoids
Consider two long co-axial solenoids, length \(l\), inner radius \(r_1\), outer radius \(r_2\).
- Magnetic field due to current \(I_2\) in solenoid 2:
\[ B = \mu_0 n_2 I_2 \]
where \(n_2\) = turns per unit length of solenoid 2. - Flux through solenoid 1:
\[ \Phi_1 = B \cdot A_1 = \mu_0 n_2 I_2 \cdot \pi r_1^2 \] - Total flux linkage:
\[ N_1 \Phi_1 = \mu_0 n_1 l \cdot n_2 I_2 \cdot \pi r_1^2 \] - Comparing with \( N_1 \Phi_1 = M I_2 \), we get:
\[ M = \mu_0 n_1 n_2 \pi r_1^2 l \]
If the medium has relative permeability \(\mu_r\), then
\[ M = \mu_0 \mu_r n_1 n_2 \pi r_1^2 l \]
Key Points
- \(M\) depends only on geometry of the coils and the medium, not on the current.
- SI unit of \(M\) is henry (H).
- Mutual inductance is symmetric: \( M_{12} = M_{21} \).
Applications
- Transformers: step-up and step-down voltages.
- Wireless charging: induced emf in nearby coil.
- Induction cooktops and guitar pickups.
Worked Example
Two long co-axial solenoids of length \(0.5\,\text{m}\). Solenoid 1 has 1000 turns, radius \(5\,\text{cm}\); Solenoid 2 has 2000 turns, radius \(10\,\text{cm}\). Find the mutual inductance (air core).
Here, \(n_1 = \tfrac{1000}{0.5} = 2000\,\text{turns/m}\), \(n_2 = \tfrac{2000}{0.5} = 4000\,\text{turns/m}\), \(r_1 = 0.05\,\text{m}\).
\( M = \mu_0 n_1 n_2 \pi r_1^2 l \)
\( = 4\pi \times 10^{-7} \times 2000 \times 4000 \times \pi (0.05)^2 \times 0.5 \)
\( \approx 0.039\,\text{H} \)
Answer: Mutual inductance = 39 mH.